40a^2=65a

Solution for 40a^2=65a equation:

40a^2=65a

We move all terms to the left:

40a^2-(65a)=0

a = 40; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·40·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*40}=\frac{0}{80}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*40}=\frac{130}{80}
=1+5/8
$